6+2(y-3)=y-3(1-2y)

Solution for 6+2(y-3)=y-3(1-2y) equation:

6+2(y-3)=y-3(1-2y)

We move all terms to the left:

6+2(y-3)-(y-3(1-2y))=0

We add all the numbers together, and all the variables

2(y-3)-(y-3(-2y+1))+6=0

We multiply parentheses

2y-(y-3(-2y+1))-6+6=0


We calculate terms in parentheses: -(y-3(-2y+1)), so:

y-3(-2y+1)

We multiply parentheses

y+6y-3

We add all the numbers together, and all the variables

7y-3

Back to the equation:

-(7y-3)


We add all the numbers together, and all the variables

2y-(7y-3)=0

We get rid of parentheses

2y-7y+3=0

We add all the numbers together, and all the variables

-5y+3=0

We move all terms containing y to the left, all other terms to the right

-5y=-3

y=-3/-5

y=3/5