6+2(z-3)=-7z+1

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Solution for 6+2(z-3)=-7z+1 equation: 



6+2(z-3)=-7z+1

We move all terms to the left:

6+2(z-3)-(-7z+1)=0

We multiply parentheses

2z-(-7z+1)-6+6=0

We get rid of parentheses

2z+7z-1-6+6=0

We add all the numbers together, and all the variables

9z-1=0

We move all terms containing z to the left, all other terms to the right

9z=1

z=1/9

z=1/9

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