6+2/5(2n-20)=10

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Solution for 6+2/5(2n-20)=10 equation: 


n in (-oo:+oo)

(2/5)*(2*n-20)+6 = 10 // - 10

(2/5)*(2*n-20)-10+6 = 0

2/5*(2*n-20)-10+6 = 0

2/5*(2*n-20)-10+6 = 0

4/5*n-18+6 = 0

4/5*n-12 = 0

4/5*n-12 = 0

4/5*n-12 = 0 // + 12

4/5*n = 12 // : 4/5

n = 12/4/5

n = 15

n = 15

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