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6+2x=10+2(x-4)
We move all terms to the left:
6+2x-(10+2(x-4))=0
We calculate terms in parentheses: -(10+2(x-4)), so:We get rid of parentheses
10+2(x-4)
determiningTheFunctionDomain 2(x-4)+10
We multiply parentheses
2x-8+10
We add all the numbers together, and all the variables
2x+2
Back to the equation:
-(2x+2)
2x-2x-2+6=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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