6+2x=2(-x-3)-8

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Solution for 6+2x=2(-x-3)-8 equation: 



6+2x=2(-x-3)-8

We move all terms to the left:

6+2x-(2(-x-3)-8)=0

We add all the numbers together, and all the variables

2x-(2(-1x-3)-8)+6=0



We calculate terms in parentheses: -(2(-1x-3)-8), so:

2(-1x-3)-8

We multiply parentheses

-2x-6-8

We add all the numbers together, and all the variables

-2x-14

Back to the equation:

-(-2x-14)



We get rid of parentheses

2x+2x+14+6=0

We add all the numbers together, and all the variables

4x+20=0

We move all terms containing x to the left, all other terms to the right

4x=-20

x=-20/4

x=-5

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