6+2x=3(2+2x)-5(-2+x)

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Solution for 6+2x=3(2+2x)-5(-2+x) equation: 



6+2x=3(2+2x)-5(-2+x)

We move all terms to the left:

6+2x-(3(2+2x)-5(-2+x))=0

We add all the numbers together, and all the variables

2x-(3(2x+2)-5(x-2))+6=0



We calculate terms in parentheses: -(3(2x+2)-5(x-2)), so:

3(2x+2)-5(x-2)

We multiply parentheses

6x-5x+6+10

We add all the numbers together, and all the variables

x+16

Back to the equation:

-(x+16)



We get rid of parentheses

2x-x-16+6=0

We add all the numbers together, and all the variables

x-10=0

We move all terms containing x to the left, all other terms to the right

x=10

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