6+2y-3(y+1)=5y+4(y+7)+7

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Solution for 6+2y-3(y+1)=5y+4(y+7)+7 equation: 



6+2y-3(y+1)=5y+4(y+7)+7

We move all terms to the left:

6+2y-3(y+1)-(5y+4(y+7)+7)=0

We multiply parentheses

2y-3y-(5y+4(y+7)+7)-3+6=0



We calculate terms in parentheses: -(5y+4(y+7)+7), so:

5y+4(y+7)+7

We multiply parentheses

5y+4y+28+7

We add all the numbers together, and all the variables

9y+35

Back to the equation:

-(9y+35)



We add all the numbers together, and all the variables

-1y-(9y+35)+3=0

We get rid of parentheses

-1y-9y-35+3=0

We add all the numbers together, and all the variables

-10y-32=0

We move all terms containing y to the left, all other terms to the right

-10y=32

y=32/-10

y=-3+1/5

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