6+2z=41-5z

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Solution for 6+2z=41-5z equation: 



6+2z=41-5z

We move all terms to the left:

6+2z-(41-5z)=0

We add all the numbers together, and all the variables

2z-(-5z+41)+6=0

We get rid of parentheses

2z+5z-41+6=0

We add all the numbers together, and all the variables

7z-35=0

We move all terms containing z to the left, all other terms to the right

7z=35

z=35/7

z=5

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