6+3(-3+6b)=-3(1+8b)-7b

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Solution for 6+3(-3+6b)=-3(1+8b)-7b equation: 



6+3(-3+6b)=-3(1+8b)-7b

We move all terms to the left:

6+3(-3+6b)-(-3(1+8b)-7b)=0

We add all the numbers together, and all the variables

3(6b-3)-(-3(8b+1)-7b)+6=0

We multiply parentheses

18b-(-3(8b+1)-7b)-9+6=0



We calculate terms in parentheses: -(-3(8b+1)-7b), so:

-3(8b+1)-7b

We add all the numbers together, and all the variables

-7b-3(8b+1)

We multiply parentheses

-7b-24b-3

We add all the numbers together, and all the variables

-31b-3

Back to the equation:

-(-31b-3)



We add all the numbers together, and all the variables

18b-(-31b-3)-3=0

We get rid of parentheses

18b+31b+3-3=0

We add all the numbers together, and all the variables

49b=0

b=0/49

b=0

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