6+3(-3+6b)=-3(1+8b)-7b

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Solution for 6+3(-3+6b)=-3(1+8b)-7b equation:



6+3(-3+6b)=-3(1+8b)-7b
We move all terms to the left:
6+3(-3+6b)-(-3(1+8b)-7b)=0
We add all the numbers together, and all the variables
3(6b-3)-(-3(8b+1)-7b)+6=0
We multiply parentheses
18b-(-3(8b+1)-7b)-9+6=0
We calculate terms in parentheses: -(-3(8b+1)-7b), so:
-3(8b+1)-7b
We add all the numbers together, and all the variables
-7b-3(8b+1)
We multiply parentheses
-7b-24b-3
We add all the numbers together, and all the variables
-31b-3
Back to the equation:
-(-31b-3)
We add all the numbers together, and all the variables
18b-(-31b-3)-3=0
We get rid of parentheses
18b+31b+3-3=0
We add all the numbers together, and all the variables
49b=0
b=0/49
b=0

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