6+3(2u-2)=-2(7u-2)+8u

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Solution for 6+3(2u-2)=-2(7u-2)+8u equation: 



6+3(2u-2)=-2(7u-2)+8u

We move all terms to the left:

6+3(2u-2)-(-2(7u-2)+8u)=0

We multiply parentheses

6u-(-2(7u-2)+8u)-6+6=0



We calculate terms in parentheses: -(-2(7u-2)+8u), so:

-2(7u-2)+8u

We add all the numbers together, and all the variables

8u-2(7u-2)

We multiply parentheses

8u-14u+4

We add all the numbers together, and all the variables

-6u+4

Back to the equation:

-(-6u+4)



We add all the numbers together, and all the variables

6u-(-6u+4)=0

We get rid of parentheses

6u+6u-4=0

We add all the numbers together, and all the variables

12u-4=0

We move all terms containing u to the left, all other terms to the right

12u=4

u=4/12

u=1/3

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