6+3(3w-5+7w)=-(2w-1)

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Solution for 6+3(3w-5+7w)=-(2w-1) equation: 



6+3(3w-5+7w)=-(2w-1)

We move all terms to the left:

6+3(3w-5+7w)-(-(2w-1))=0

We add all the numbers together, and all the variables

3(10w-5)-(-(2w-1))+6=0

We multiply parentheses

30w-(-(2w-1))-15+6=0



We calculate terms in parentheses: -(-(2w-1)), so:

-(2w-1)

We get rid of parentheses

-2w+1

Back to the equation:

-(-2w+1)



We add all the numbers together, and all the variables

30w-(-2w+1)-9=0

We get rid of parentheses

30w+2w-1-9=0

We add all the numbers together, and all the variables

32w-10=0

We move all terms containing w to the left, all other terms to the right

32w=10

w=10/32

w=5/16

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