6+3(3w-5+7w)=-(2w-1)

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Solution for 6+3(3w-5+7w)=-(2w-1) equation:



6+3(3w-5+7w)=-(2w-1)
We move all terms to the left:
6+3(3w-5+7w)-(-(2w-1))=0
We add all the numbers together, and all the variables
3(10w-5)-(-(2w-1))+6=0
We multiply parentheses
30w-(-(2w-1))-15+6=0
We calculate terms in parentheses: -(-(2w-1)), so:
-(2w-1)
We get rid of parentheses
-2w+1
Back to the equation:
-(-2w+1)
We add all the numbers together, and all the variables
30w-(-2w+1)-9=0
We get rid of parentheses
30w+2w-1-9=0
We add all the numbers together, and all the variables
32w-10=0
We move all terms containing w to the left, all other terms to the right
32w=10
w=10/32
w=5/16

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