6+3(3x-4)=8-4(2x+1)

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Solution for 6+3(3x-4)=8-4(2x+1) equation: 



6+3(3x-4)=8-4(2x+1)

We move all terms to the left:

6+3(3x-4)-(8-4(2x+1))=0

We multiply parentheses

9x-(8-4(2x+1))-12+6=0



We calculate terms in parentheses: -(8-4(2x+1)), so:

8-4(2x+1)

determiningTheFunctionDomain
-4(2x+1)+8

We multiply parentheses

-8x-4+8

We add all the numbers together, and all the variables

-8x+4

Back to the equation:

-(-8x+4)



We add all the numbers together, and all the variables

9x-(-8x+4)-6=0

We get rid of parentheses

9x+8x-4-6=0

We add all the numbers together, and all the variables

17x-10=0

We move all terms containing x to the left, all other terms to the right

17x=10

x=10/17

x=10/17

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