6+3(4a-3)=12+5a

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Solution for 6+3(4a-3)=12+5a equation: 



6+3(4a-3)=12+5a

We move all terms to the left:

6+3(4a-3)-(12+5a)=0

We add all the numbers together, and all the variables

3(4a-3)-(5a+12)+6=0

We multiply parentheses

12a-(5a+12)-9+6=0

We get rid of parentheses

12a-5a-12-9+6=0

We add all the numbers together, and all the variables

7a-15=0

We move all terms containing a to the left, all other terms to the right

7a=15

a=15/7

a=2+1/7

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