6+3(6x-7)=40x+-28

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Solution for 6+3(6x-7)=40x+-28 equation: 



6+3(6x-7)=40x+-28

We move all terms to the left:

6+3(6x-7)-(40x+-28)=0

We add all the numbers together, and all the variables

3(6x-7)-(40x-28)+6=0

We multiply parentheses

18x-(40x-28)-21+6=0

We get rid of parentheses

18x-40x+28-21+6=0

We add all the numbers together, and all the variables

-22x+13=0

We move all terms containing x to the left, all other terms to the right

-22x=-13

x=-13/-22

x=13/22

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