6+3(c-4)=2(-5c-3)+13c

Solution for 6+3(c-4)=2(-5c-3)+13c equation:

6+3(c-4)=2(-5c-3)+13c

We move all terms to the left:

6+3(c-4)-(2(-5c-3)+13c)=0

We multiply parentheses

3c-(2(-5c-3)+13c)-12+6=0


We calculate terms in parentheses: -(2(-5c-3)+13c), so:

2(-5c-3)+13c

We add all the numbers together, and all the variables

13c+2(-5c-3)

We multiply parentheses

13c-10c-6

We add all the numbers together, and all the variables

3c-6

Back to the equation:

-(3c-6)


We add all the numbers together, and all the variables

3c-(3c-6)-6=0

We get rid of parentheses

3c-3c+6-6=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0