6+3(k-4)=k+3+5k

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Solution for 6+3(k-4)=k+3+5k equation:



6+3(k-4)=k+3+5k
We move all terms to the left:
6+3(k-4)-(k+3+5k)=0
We add all the numbers together, and all the variables
3(k-4)-(6k+3)+6=0
We multiply parentheses
3k-(6k+3)-12+6=0
We get rid of parentheses
3k-6k-3-12+6=0
We add all the numbers together, and all the variables
-3k-9=0
We move all terms containing k to the left, all other terms to the right
-3k=9
k=9/-3
k=-3

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