6+3(n-4)=2(n-2)

Solution for 6+3(n-4)=2(n-2) equation:

Simplifying
6 + 3(n + -4) = 2(n + -2)

Reorder the terms:
6 + 3(-4 + n) = 2(n + -2)
6 + (-4 * 3 + n * 3) = 2(n + -2)
6 + (-12 + 3n) = 2(n + -2)

Combine like terms: 6 + -12 = -6
-6 + 3n = 2(n + -2)

Reorder the terms:
-6 + 3n = 2(-2 + n)
-6 + 3n = (-2 * 2 + n * 2)
-6 + 3n = (-4 + 2n)

Solving
-6 + 3n = -4 + 2n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2n' to each side of the equation.
-6 + 3n + -2n = -4 + 2n + -2n

Combine like terms: 3n + -2n = 1n
-6 + 1n = -4 + 2n + -2n

Combine like terms: 2n + -2n = 0
-6 + 1n = -4 + 0
-6 + 1n = -4

Add '6' to each side of the equation.
-6 + 6 + 1n = -4 + 6

Combine like terms: -6 + 6 = 0
0 + 1n = -4 + 6
1n = -4 + 6

Combine like terms: -4 + 6 = 2
1n = 2

Divide each side by '1'.
n = 2

Simplifying
n = 2