6+3(x-2)=4(x+1)

Solution for 6+3(x-2)=4(x+1) equation:

6+3(x-2)=4(x+1)

We move all terms to the left:

6+3(x-2)-(4(x+1))=0

We multiply parentheses

3x-(4(x+1))-6+6=0


We calculate terms in parentheses: -(4(x+1)), so:

4(x+1)

We multiply parentheses

4x+4

Back to the equation:

-(4x+4)


We add all the numbers together, and all the variables

3x-(4x+4)=0

We get rid of parentheses

3x-4x-4=0

We add all the numbers together, and all the variables

-1x-4=0

We move all terms containing x to the left, all other terms to the right

-x=4

x=4/-1

x=-4