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6+3(x-4)=9-9(x-7)
We move all terms to the left:
6+3(x-4)-(9-9(x-7))=0
We multiply parentheses
3x-(9-9(x-7))-12+6=0
We calculate terms in parentheses: -(9-9(x-7)), so:We add all the numbers together, and all the variables
9-9(x-7)
determiningTheFunctionDomain -9(x-7)+9
We multiply parentheses
-9x+63+9
We add all the numbers together, and all the variables
-9x+72
Back to the equation:
-(-9x+72)
3x-(-9x+72)-6=0
We get rid of parentheses
3x+9x-72-6=0
We add all the numbers together, and all the variables
12x-78=0
We move all terms containing x to the left, all other terms to the right
12x=78
x=78/12
x=6+1/2
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