6+3(y+1)=4y+10

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Solution for 6+3(y+1)=4y+10 equation: 



6+3(y+1)=4y+10

We move all terms to the left:

6+3(y+1)-(4y+10)=0

We multiply parentheses

3y-(4y+10)+3+6=0

We get rid of parentheses

3y-4y-10+3+6=0

We add all the numbers together, and all the variables

-1y-1=0

We move all terms containing y to the left, all other terms to the right

-y=1

y=1/-1

y=-1

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