6+3(y-4)=19

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Solution for 6+3(y-4)=19 equation: 



6+3(y-4)=19

We move all terms to the left:

6+3(y-4)-(19)=0

We add all the numbers together, and all the variables

3(y-4)-13=0

We multiply parentheses

3y-12-13=0

We add all the numbers together, and all the variables

3y-25=0

We move all terms containing y to the left, all other terms to the right

3y=25

y=25/3

y=8+1/3

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