6+3(z-2)=-4z+1

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Solution for 6+3(z-2)=-4z+1 equation: 



6+3(z-2)=-4z+1

We move all terms to the left:

6+3(z-2)-(-4z+1)=0

We multiply parentheses

3z-(-4z+1)-6+6=0

We get rid of parentheses

3z+4z-1-6+6=0

We add all the numbers together, and all the variables

7z-1=0

We move all terms containing z to the left, all other terms to the right

7z=1

z=1/7

z=1/7

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