6+3/4x=x-4

Solution for 6+3/4x=x-4 equation:

6+3/4x=x-4

We move all terms to the left:

6+3/4x-(x-4)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We get rid of parentheses

3/4x-x+4+6=0

We multiply all the terms by the denominator


-x*4x+4*4x+6*4x+3=0

Wy multiply elements

-4x^2+16x+24x+3=0

We add all the numbers together, and all the variables

-4x^2+40x+3=0

a = -4; b = 40; c = +3;
Δ = b2-4ac
Δ = 402-4·(-4)·3
Δ = 1648
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1648}=\sqrt{16*103}=\sqrt{16}*\sqrt{103}=4\sqrt{103}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-4\sqrt{103}}{2*-4}=\frac{-40-4\sqrt{103}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+4\sqrt{103}}{2*-4}=\frac{-40+4\sqrt{103}}{-8}
$