6+3x-2=x+4-2x+12

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Solution for 6+3x-2=x+4-2x+12 equation: 



6+3x-2=x+4-2x+12

We move all terms to the left:

6+3x-2-(x+4-2x+12)=0

We add all the numbers together, and all the variables

3x-(-1x+16)+6-2=0

We add all the numbers together, and all the variables

3x-(-1x+16)+4=0

We get rid of parentheses

3x+1x-16+4=0

We add all the numbers together, and all the variables

4x-12=0

We move all terms containing x to the left, all other terms to the right

4x=12

x=12/4

x=3

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