6+3z-1=9z+19+4z

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Solution for 6+3z-1=9z+19+4z equation: 



6+3z-1=9z+19+4z

We move all terms to the left:

6+3z-1-(9z+19+4z)=0

We add all the numbers together, and all the variables

3z-(13z+19)+6-1=0

We add all the numbers together, and all the variables

3z-(13z+19)+5=0

We get rid of parentheses

3z-13z-19+5=0

We add all the numbers together, and all the variables

-10z-14=0

We move all terms containing z to the left, all other terms to the right

-10z=14

z=14/-10

z=-1+2/5

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