6+4(2v-2)=5(4v-10)

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Solution for 6+4(2v-2)=5(4v-10) equation: 



6+4(2v-2)=5(4v-10)

We move all terms to the left:

6+4(2v-2)-(5(4v-10))=0

We multiply parentheses

8v-(5(4v-10))-8+6=0



We calculate terms in parentheses: -(5(4v-10)), so:

5(4v-10)

We multiply parentheses

20v-50

Back to the equation:

-(20v-50)



We add all the numbers together, and all the variables

8v-(20v-50)-2=0

We get rid of parentheses

8v-20v+50-2=0

We add all the numbers together, and all the variables

-12v+48=0

We move all terms containing v to the left, all other terms to the right

-12v=-48

v=-48/-12

v=+4

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