6+4(2x-3)=5-(x+2)

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Solution for 6+4(2x-3)=5-(x+2) equation: 



6+4(2x-3)=5-(x+2)

We move all terms to the left:

6+4(2x-3)-(5-(x+2))=0

We multiply parentheses

8x-(5-(x+2))-12+6=0



We calculate terms in parentheses: -(5-(x+2)), so:

5-(x+2)

determiningTheFunctionDomain
-(x+2)+5

We get rid of parentheses

-x-2+5

We add all the numbers together, and all the variables

-1x+3

Back to the equation:

-(-1x+3)



We add all the numbers together, and all the variables

8x-(-1x+3)-6=0

We get rid of parentheses

8x+1x-3-6=0

We add all the numbers together, and all the variables

9x-9=0

We move all terms containing x to the left, all other terms to the right

9x=9

x=9/9

x=1

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