6+4(3-k)=3(-2k+9)

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Solution for 6+4(3-k)=3(-2k+9) equation: 



6+4(3-k)=3(-2k+9)

We move all terms to the left:

6+4(3-k)-(3(-2k+9))=0

We add all the numbers together, and all the variables

4(-1k+3)-(3(-2k+9))+6=0

We multiply parentheses

-4k-(3(-2k+9))+12+6=0



We calculate terms in parentheses: -(3(-2k+9)), so:

3(-2k+9)

We multiply parentheses

-6k+27

Back to the equation:

-(-6k+27)



We add all the numbers together, and all the variables

-4k-(-6k+27)+18=0

We get rid of parentheses

-4k+6k-27+18=0

We add all the numbers together, and all the variables

2k-9=0

We move all terms containing k to the left, all other terms to the right

2k=9

k=9/2

k=4+1/2

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