6+4(3x+1)=2(4x-3)+32

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Solution for 6+4(3x+1)=2(4x-3)+32 equation: 



6+4(3x+1)=2(4x-3)+32

We move all terms to the left:

6+4(3x+1)-(2(4x-3)+32)=0

We multiply parentheses

12x-(2(4x-3)+32)+4+6=0



We calculate terms in parentheses: -(2(4x-3)+32), so:

2(4x-3)+32

We multiply parentheses

8x-6+32

We add all the numbers together, and all the variables

8x+26

Back to the equation:

-(8x+26)



We add all the numbers together, and all the variables

12x-(8x+26)+10=0

We get rid of parentheses

12x-8x-26+10=0

We add all the numbers together, and all the variables

4x-16=0

We move all terms containing x to the left, all other terms to the right

4x=16

x=16/4

x=4

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