6+4(4v-1)=-2(2v-2)+8v

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Solution for 6+4(4v-1)=-2(2v-2)+8v equation: 



6+4(4v-1)=-2(2v-2)+8v

We move all terms to the left:

6+4(4v-1)-(-2(2v-2)+8v)=0

We multiply parentheses

16v-(-2(2v-2)+8v)-4+6=0



We calculate terms in parentheses: -(-2(2v-2)+8v), so:

-2(2v-2)+8v

We add all the numbers together, and all the variables

8v-2(2v-2)

We multiply parentheses

8v-4v+4

We add all the numbers together, and all the variables

4v+4

Back to the equation:

-(4v+4)



We add all the numbers together, and all the variables

16v-(4v+4)+2=0

We get rid of parentheses

16v-4v-4+2=0

We add all the numbers together, and all the variables

12v-2=0

We move all terms containing v to the left, all other terms to the right

12v=2

v=2/12

v=1/6

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