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6+4(5x-6)=9-5(2x+1)
We move all terms to the left:
6+4(5x-6)-(9-5(2x+1))=0
We multiply parentheses
20x-(9-5(2x+1))-24+6=0
We calculate terms in parentheses: -(9-5(2x+1)), so:We add all the numbers together, and all the variables
9-5(2x+1)
determiningTheFunctionDomain -5(2x+1)+9
We multiply parentheses
-10x-5+9
We add all the numbers together, and all the variables
-10x+4
Back to the equation:
-(-10x+4)
20x-(-10x+4)-18=0
We get rid of parentheses
20x+10x-4-18=0
We add all the numbers together, and all the variables
30x-22=0
We move all terms containing x to the left, all other terms to the right
30x=22
x=22/30
x=11/15
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