6+4(m+4)=2(1+m)

Solution for 6+4(m+4)=2(1+m) equation:

6+4(m+4)=2(1+m)

We move all terms to the left:

6+4(m+4)-(2(1+m))=0

We add all the numbers together, and all the variables

4(m+4)-(2(m+1))+6=0

We multiply parentheses

4m-(2(m+1))+16+6=0


We calculate terms in parentheses: -(2(m+1)), so:

2(m+1)

We multiply parentheses

2m+2

Back to the equation:

-(2m+2)


We add all the numbers together, and all the variables

4m-(2m+2)+22=0

We get rid of parentheses

4m-2m-2+22=0

We add all the numbers together, and all the variables

2m+20=0

We move all terms containing m to the left, all other terms to the right

2m=-20

m=-20/2

m=-10