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6+4/6x=9/10x
We move all terms to the left:
6+4/6x-(9/10x)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 10x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
4/6x-(+9/10x)+6=0
We get rid of parentheses
4/6x-9/10x+6=0
We calculate fractions
40x/60x^2+(-54x)/60x^2+6=0
We multiply all the terms by the denominator
40x+(-54x)+6*60x^2=0
Wy multiply elements
360x^2+40x+(-54x)=0
We get rid of parentheses
360x^2+40x-54x=0
We add all the numbers together, and all the variables
360x^2-14x=0
a = 360; b = -14; c = 0;
Δ = b2-4ac
Δ = -142-4·360·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-14}{2*360}=\frac{0}{720} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+14}{2*360}=\frac{28}{720} =7/180 $
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