6+4f=6(2f+7)+10f

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Solution for 6+4f=6(2f+7)+10f equation: 



6+4f=6(2f+7)+10f

We move all terms to the left:

6+4f-(6(2f+7)+10f)=0



We calculate terms in parentheses: -(6(2f+7)+10f), so:

6(2f+7)+10f

We add all the numbers together, and all the variables

10f+6(2f+7)

We multiply parentheses

10f+12f+42

We add all the numbers together, and all the variables

22f+42

Back to the equation:

-(22f+42)



We get rid of parentheses

4f-22f-42+6=0

We add all the numbers together, and all the variables

-18f-36=0

We move all terms containing f to the left, all other terms to the right

-18f=36

f=36/-18

f=-2

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