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6+5x-10=2(x+2)+3x
We move all terms to the left:
6+5x-10-(2(x+2)+3x)=0
We add all the numbers together, and all the variables
5x-(2(x+2)+3x)-4=0
We calculate terms in parentheses: -(2(x+2)+3x), so:We get rid of parentheses
2(x+2)+3x
We add all the numbers together, and all the variables
3x+2(x+2)
We multiply parentheses
3x+2x+4
We add all the numbers together, and all the variables
5x+4
Back to the equation:
-(5x+4)
5x-5x-4-4=0
We add all the numbers together, and all the variables
-8!=0
There is no solution for this equation
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