6+6(2t-1)=3(t+7)

Solution for 6+6(2t-1)=3(t+7) equation:

6+6(2t-1)=3(t+7)

We move all terms to the left:

6+6(2t-1)-(3(t+7))=0

We multiply parentheses

12t-(3(t+7))-6+6=0


We calculate terms in parentheses: -(3(t+7)), so:

3(t+7)

We multiply parentheses

3t+21

Back to the equation:

-(3t+21)


We add all the numbers together, and all the variables

12t-(3t+21)=0

We get rid of parentheses

12t-3t-21=0

We add all the numbers together, and all the variables

9t-21=0

We move all terms containing t to the left, all other terms to the right

9t=21

t=21/9

t=2+1/3