6+6x=2(3x+33)+x

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Solution for 6+6x=2(3x+33)+x equation: 



6+6x=2(3x+33)+x

We move all terms to the left:

6+6x-(2(3x+33)+x)=0



We calculate terms in parentheses: -(2(3x+33)+x), so:

2(3x+33)+x

We add all the numbers together, and all the variables

x+2(3x+33)

We multiply parentheses

x+6x+66

We add all the numbers together, and all the variables

7x+66

Back to the equation:

-(7x+66)



We get rid of parentheses

6x-7x-66+6=0

We add all the numbers together, and all the variables

-1x-60=0

We move all terms containing x to the left, all other terms to the right

-x=60

x=60/-1

x=-60

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