6+8(x-4)-2x+10=12-4x+6(2+x)-10

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Solution for 6+8(x-4)-2x+10=12-4x+6(2+x)-10 equation: 



6+8(x-4)-2x+10=12-4x+6(2+x)-10

We move all terms to the left:

6+8(x-4)-2x+10-(12-4x+6(2+x)-10)=0

We add all the numbers together, and all the variables

8(x-4)-2x-(12-4x+6(x+2)-10)+6+10=0

We add all the numbers together, and all the variables

-2x+8(x-4)-(12-4x+6(x+2)-10)+16=0

We multiply parentheses

-2x+8x-(12-4x+6(x+2)-10)-32+16=0



We calculate terms in parentheses: -(12-4x+6(x+2)-10), so:

12-4x+6(x+2)-10

determiningTheFunctionDomain
-4x+6(x+2)+12-10

We add all the numbers together, and all the variables

-4x+6(x+2)+2

We multiply parentheses

-4x+6x+12+2

We add all the numbers together, and all the variables

2x+14

Back to the equation:

-(2x+14)



We add all the numbers together, and all the variables

6x-(2x+14)-16=0

We get rid of parentheses

6x-2x-14-16=0

We add all the numbers together, and all the variables

4x-30=0

We move all terms containing x to the left, all other terms to the right

4x=30

x=30/4

x=7+1/2

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