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6+8/2x=5x
We move all terms to the left:
6+8/2x-(5x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-5x+8/2x+6=0
We multiply all the terms by the denominator
-5x*2x+6*2x+8=0
Wy multiply elements
-10x^2+12x+8=0
a = -10; b = 12; c = +8;
Δ = b2-4ac
Δ = 122-4·(-10)·8
Δ = 464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{464}=\sqrt{16*29}=\sqrt{16}*\sqrt{29}=4\sqrt{29}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{29}}{2*-10}=\frac{-12-4\sqrt{29}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{29}}{2*-10}=\frac{-12+4\sqrt{29}}{-20} $
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