6+8b=-b-3(b-2)

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Solution for 6+8b=-b-3(b-2) equation: 



6+8b=-b-3(b-2)

We move all terms to the left:

6+8b-(-b-3(b-2))=0



We calculate terms in parentheses: -(-b-3(b-2)), so:

-b-3(b-2)

We add all the numbers together, and all the variables

-1b-3(b-2)

We multiply parentheses

-1b-3b+6

We add all the numbers together, and all the variables

-4b+6

Back to the equation:

-(-4b+6)



We get rid of parentheses

8b+4b-6+6=0

We add all the numbers together, and all the variables

12b=0

b=0/12

b=0

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