If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6+8f(f=4)
We move all terms to the left:
6+8f(f-(4))=0
We multiply parentheses
8f^2-32f+6=0
a = 8; b = -32; c = +6;
Δ = b2-4ac
Δ = -322-4·8·6
Δ = 832
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{832}=\sqrt{64*13}=\sqrt{64}*\sqrt{13}=8\sqrt{13}$$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-8\sqrt{13}}{2*8}=\frac{32-8\sqrt{13}}{16} $$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+8\sqrt{13}}{2*8}=\frac{32+8\sqrt{13}}{16} $
| 3(x+2)+6=27 | | 27^x-2=81^-x | | 5(v-5)=-8v+1 | | 16155.3=21*h | | 3x=-7x-80 | | d+904=-754 | | 1/10+1.1=-16=2x | | 5^(x)*5^(6)*5^(x+2)=5^(14) | | 5(-1x-10)=-15 | | -9x+1=-20 | | 3(7+2)=ff= | | 5^(2x+8)=5^(14) | | 31=6.2t-10.33 | | ^(2x+8)=5^(14) | | 32=6.2t-10.33 | | x-0.10x-70=0.35(70) | | 2.69-3.64x=27.78x | | 30=6.2t-10.33 | | 15x^2-29x-14=x(5x+2) | | 7(3-6x)=-21 | | -2=+v/4 | | 4x^2+16x+65=0 | | 3(3t-14)=-14 | | 8^2x-6=4^3x-1 | | 5p+8=7p=2 | | 12y-16=-4 | | t/16-3/4=5/8 | | Y=2t+5 | | -2(8-6x)=80 | | 1.5x+3.5=2^x | | 3k^2+20k+25=0 | | x-0.1x-70=0.35(70) |