6+s=4s-3(s+2)

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Solution for 6+s=4s-3(s+2) equation: 



6+s=4s-3(s+2)

We move all terms to the left:

6+s-(4s-3(s+2))=0



We calculate terms in parentheses: -(4s-3(s+2)), so:

4s-3(s+2)

We multiply parentheses

4s-3s-6

We add all the numbers together, and all the variables

s-6

Back to the equation:

-(s-6)



We get rid of parentheses

s-s+6+6=0

We add all the numbers together, and all the variables

12!=0

There is no solution for this equation

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