6+t3(5t+4t)=12(2+-5

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Solution for 6+t3(5t+4t)=12(2+-5 equation: 



6+t3(5t+4t)=12(2+-5

We move all terms to the left:

6+t3(5t+4t)-(12(2+-5)=0

We add all the numbers together, and all the variables

t3(+9t)+6-(12(-3)=0

We add all the numbers together, and all the variables

t3(+9t)=0

We multiply parentheses

9t^4=0

We do not support etpression: t^4

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