6+x=2((x/2)+3)

Solution for 6+x=2((x/2)+3) equation:

6+x=2((x/2)+3)

We move all terms to the left:

6+x-(2((x/2)+3))=0

We add all the numbers together, and all the variables

x-(2((+x/2)+3))+6=0

We multiply all the terms by the denominator


x*2)+3))-(2((+x+6*2)+3))=0

We add all the numbers together, and all the variables

x*2)+3))-(2((x+12)+3))=0

We add all the numbers together, and all the variables

x*2)+3))-(2((x=0

Wy multiply elements

2x^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$