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6+x=3(2-x)
We move all terms to the left:
6+x-(3(2-x))=0
We add all the numbers together, and all the variables
x-(3(-1x+2))+6=0
We calculate terms in parentheses: -(3(-1x+2)), so:We get rid of parentheses
3(-1x+2)
We multiply parentheses
-3x+6
Back to the equation:
-(-3x+6)
x+3x-6+6=0
We add all the numbers together, and all the variables
4x=0
x=0/4
x=0
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