6-((1-6z)/2)=(7/10)+6z

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Solution for 6-((1-6z)/2)=(7/10)+6z equation: 



6-((1-6z)/2)=(7/10)+6z

We move all terms to the left:

6-((1-6z)/2)-((7/10)+6z)=0



Domain of the equation: 10)+6z)!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

-((-6z+1)/2)-((+7/10)+6z)+6=0

We calculate fractions


(60z+6z)-10)/2*10)+6z))+()/2*10)+6z))+6=0

We can not solve this equation

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