6-(-1+7z)=3(-z-3)

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Solution for 6-(-1+7z)=3(-z-3) equation: 



6-(-1+7z)=3(-z-3)

We move all terms to the left:

6-(-1+7z)-(3(-z-3))=0

We add all the numbers together, and all the variables

-(7z-1)-(3(-1z-3))+6=0

We get rid of parentheses

-7z-(3(-1z-3))+1+6=0



We calculate terms in parentheses: -(3(-1z-3)), so:

3(-1z-3)

We multiply parentheses

-3z-9

Back to the equation:

-(-3z-9)



We add all the numbers together, and all the variables

-7z-(-3z-9)+7=0

We get rid of parentheses

-7z+3z+9+7=0

We add all the numbers together, and all the variables

-4z+16=0

We move all terms containing z to the left, all other terms to the right

-4z=-16

z=-16/-4

z=+4

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