6-(-y-6)=4(y+3)-8(y+3)

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Solution for 6-(-y-6)=4(y+3)-8(y+3) equation: 



6-(-y-6)=4(y+3)-8(y+3)

We move all terms to the left:

6-(-y-6)-(4(y+3)-8(y+3))=0

We add all the numbers together, and all the variables

-(-1y-6)-(4(y+3)-8(y+3))+6=0

We get rid of parentheses

1y-(4(y+3)-8(y+3))+6+6=0



We calculate terms in parentheses: -(4(y+3)-8(y+3)), so:

4(y+3)-8(y+3)

We multiply parentheses

4y-8y+12-24

We add all the numbers together, and all the variables

-4y-12

Back to the equation:

-(-4y-12)



We add all the numbers together, and all the variables

y-(-4y-12)+12=0

We get rid of parentheses

y+4y+12+12=0

We add all the numbers together, and all the variables

5y+24=0

We move all terms containing y to the left, all other terms to the right

5y=-24

y=-24/5

y=-4+4/5

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