6-(2+3b)+4b=3(b-2)-4

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Solution for 6-(2+3b)+4b=3(b-2)-4 equation:


Simplifying
6 + -1(2 + 3b) + 4b = 3(b + -2) + -4
6 + (2 * -1 + 3b * -1) + 4b = 3(b + -2) + -4
6 + (-2 + -3b) + 4b = 3(b + -2) + -4

Combine like terms: 6 + -2 = 4
4 + -3b + 4b = 3(b + -2) + -4

Combine like terms: -3b + 4b = 1b
4 + 1b = 3(b + -2) + -4

Reorder the terms:
4 + 1b = 3(-2 + b) + -4
4 + 1b = (-2 * 3 + b * 3) + -4
4 + 1b = (-6 + 3b) + -4

Reorder the terms:
4 + 1b = -6 + -4 + 3b

Combine like terms: -6 + -4 = -10
4 + 1b = -10 + 3b

Solving
4 + 1b = -10 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
4 + 1b + -3b = -10 + 3b + -3b

Combine like terms: 1b + -3b = -2b
4 + -2b = -10 + 3b + -3b

Combine like terms: 3b + -3b = 0
4 + -2b = -10 + 0
4 + -2b = -10

Add '-4' to each side of the equation.
4 + -4 + -2b = -10 + -4

Combine like terms: 4 + -4 = 0
0 + -2b = -10 + -4
-2b = -10 + -4

Combine like terms: -10 + -4 = -14
-2b = -14

Divide each side by '-2'.
b = 7

Simplifying
b = 7

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