6-(2-2y)=6+7y-(4+3y)

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Solution for 6-(2-2y)=6+7y-(4+3y) equation: 



6-(2-2y)=6+7y-(4+3y)

We move all terms to the left:

6-(2-2y)-(6+7y-(4+3y))=0

We add all the numbers together, and all the variables

-(-2y+2)-(6+7y-(3y+4))+6=0

We get rid of parentheses

2y-(6+7y-(3y+4))-2+6=0



We calculate terms in parentheses: -(6+7y-(3y+4)), so:

6+7y-(3y+4)

determiningTheFunctionDomain
7y-(3y+4)+6

We get rid of parentheses

7y-3y-4+6

We add all the numbers together, and all the variables

4y+2

Back to the equation:

-(4y+2)



We add all the numbers together, and all the variables

2y-(4y+2)+4=0

We get rid of parentheses

2y-4y-2+4=0

We add all the numbers together, and all the variables

-2y+2=0

We move all terms containing y to the left, all other terms to the right

-2y=-2

y=-2/-2

y=1

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